Area | Class 8 | Practice Set 15.2

Area | Class 8 | Practice Set 15.2

Area Class 8 Practice Set 15.2, all the examples of this practice set are solved here in the attached pdf file.

Practice-set-15.2

Here, we are asked to find out the area of the rhombus in each of the example given below.

The area of the rhombus is calculated by using the formula given below,

Area of the rhombus = 1/2 * product of lengths of diagonals or

Area of the rhombus = 1/2 * D1 * D2

where, D1 & D2 = Lengths of the diagonals of the rhombus.

Also read : Compound Interest | Class 8 | Practice Set 14.2

A rhombus is a quadrilateral whose all sides are congruent and it’s diagonals are perpendicular bisectors of each other.

The perimeter of the rhombus is calculated by using the formula,

Perimeter of the rhombus = 4 * side of the rhombus

While solving these examples we will also use the Pythagoras Theorem. The Pythagoras theorem is,

(Hypotenuse)^2 = (Base)^2 + (Height)^2

While solving the problems based on the area of the rhombus we will use all the three formulas mentioned above and by doing simple mathematical calculations we can find our required answer.

Also read : Compound Interest | Class 8 | Practice Set 14.1

The examples solved here are as follows :

1. Lengths of the diagonals of a rhombus are 15cm and 24 cm, find its area.
2. Lengths of the diagonals of a rhombus are 16.5 cm and 14.2 cm, find its area.
3. If perimeter of a rhombus is 100 cm and length of one diagonal is 48 cm, what
   is the area of the quadrilateral?
4. If length of a diagonal of a rhombus is 30 cm and its area is 240 sq cm, find
   its perimeter.

This is how we can solve the problems given in this practice set.